(3x-2)^2-2*(x-6)(x+3)=0

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Solution for (3x-2)^2-2*(x-6)(x+3)=0 equation: 



(3x-2)^2-2(x-6)(x+3)=0

We multiply parentheses ..

-2(+x^2+3x-6x-18)+(3x-2)^2=0

We multiply parentheses

-2x^2-6x+12x+(3x-2)^2+36=0

We add all the numbers together, and all the variables

-2x^2+6x+(3x-2)^2+36=0

We move all terms containing x to the left, all other terms to the right

-2x^2+6x+(3x-2)^2=-36

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